Let A and B be two events associated with a random experiment. Then, probability of the occurrence of A given that B has already occurred is called conditional probability and denoted by P(A/B)
Example : A bag contains 5 black and 4 blue balls. Two balls are drawn from the bag one by one without replacement. What is the probability of drawing a blue ball in the second draw if a black ball is already drawn in the first draw?
Let A be the event of drawing black ball in the first draw and B be the event of drawing a blue ball in the second draw. Then, P(B/A) = Probability of drawing a blue ball in the second draw given that a black ball is already drawn in the first draw.
Total Balls = 5 + 4 = 9
Since a black ball is drawn already,
total number of balls left after the first draw = 8
total number of blue balls after the first draw = 4
P(B/A) =48=12
Unit 9 Outline with Updated Homework Tuesday, May 14: Thursday, May 16: Quiz - 11.0 (Workbook 9.1 and 9.2) - Wednesday, May 22 Wednesday, May 22: Friday, May 24: Tuesday, May 28: Thursday, May 30: Monday, June 3: UNIT 9 TEST: STATISTICS AND PROBABILITY | Quiz: Wednesday, May 22nd TEST: Monday, June 3rd |