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  • SECONDARY MATH II // MODULE 1

    QUADRATIC FUNCTIONS – 1.1

    Mathematics Vision Project

    Licensed under the Creative Commons Attribution CC BY 4.0

    mathematicsvisionproject.org

    1.1

    Needhelp?Visitwww.rsgsupport.org

    READY Topic:DistributivePropertySimplifythefollowingexpressions

    1.3 2x + 7 2.−12 5x − 4

    3.5a −3a + 13 4.9x 6x − 2

    5.!"!12x + 18 6.!"

    !10a − 25b 7.!!"

    !!121x + 22

    SET Topic:RecognizingLinearExponentialandQuadraticFunctionsIneachsetof3functions,onewillbelinearandonewillbeexponential.Oneofthethreewillbeanewcategoryoffunction.Listthecharacteristicsineachtablethathelpedyoutoidentifythelinearandtheexponentialfunctions.Whataresomecharacteristicsofthenewfunction?Findanexplicitandrecursiveequationforeach.8.Linear,exponential,oranewkindoffunction?

    a.

    Typeandcharacteristics?

    Explicitequation:

    Recursiveequation:

    𝑥 𝑓(𝑥)

    6 64

    7 128

    8 256

    9 512

    10 1024

    b.

    Typeandcharacteristics?

    Explicitequation:

    Recursiveequation:

    𝑥 𝑓(𝑥)

    6 36

    7 49

    8 64

    9 81

    10 100

    c.

    Typeandcharacteristics?

    Explicitequation:

    Recursiveequation:

    𝑥 𝑓(𝑥)

    6 11

    7 13

    8 15

    9 17

    10 19

    READY, SET, GO! Name PeriodDate

    Answer:6x+21 Answer:-60x+48

    Answer:-15a2+65a Answer:54x2–18x

    Answer:8x2+12x Answer:8a2–20ab Answer:-44x2–8x

    Answer:Ratioof2betweenoutputs,Exponential.

    Answer:Goesbydifferentamounts,newkind.

    Answer:Differenceof2betweenoutputs,Linear.

    Answer:𝒇(𝒙) = 𝟐𝒙 Answer:𝒇(𝒙) = 𝒙𝟐 Answer:𝒇(𝒙) = 𝟐𝒙 − 𝟏

    Answer:𝒇(𝒙) = 𝒇(𝒙 − 𝟏) ∙ 𝟐 𝒇(𝟏) = 𝟐

    Answer:𝒇(𝒙) = 𝒇(𝒙 − 𝟏) + 𝟐𝒙 − 𝟏 𝒇(𝟔) = 𝟑𝟔

    Answer:𝒇(𝒙) = 𝒇(𝒙 − 𝟏) + 𝟐 𝒇(𝟔) = 𝟏𝟏

    Answer:Different,notexpectedstudentscancreateyet.

  • SECONDARY MATH II // MODULE 1

    QUADRATIC FUNCTIONS – 1.1

    Mathematics Vision Project

    Licensed under the Creative Commons Attribution CC BY 4.0

    mathematicsvisionproject.org

    1.1

    Needhelp?Visitwww.rsgsupport.org

    9.Linear,exponential,oranewkindoffunction?d.

    Typeandcharacteristics?

    Explicitequation:

    Recursiveequation:

    𝑥 𝑓(𝑥)

    -2 -17

    -1 -12

    0 -7

    1 -2

    2 3

    e.

    Typeandcharacteristics?

    Explicitequation:

    Recursiveequation:

    𝑥 𝑓(𝑥)

    -2 1/25

    -1 1/5

    0 1

    1 5

    2 25

    f.

    Typeandcharacteristics?

    Explicitequation:

    Recursiveequation:

    𝑥 𝑓(𝑥)

    -2 9

    -1 6

    0 5

    1 6

    2 9

    10.Graphthefunctionsfromthetablesin#8and#9.Addanyadditionalcharacteristicsyounoticefromthegraph.Placeyouraxessothatyoucanshowall5points.Identifyyourscale.Writeyourexplicitequationabovethegraph.a.Equation:

    b.Equation:

    c.Equation:

    d.Equation:

    e.Equation:

    f.Equation:

    Answer:Differenceof5betweenoutputs,Linear.

    Answer:Ratioof5betweenoutputs,Exponential.

    Answer:Differentamountsbeingadded,newkind.

    Answer:𝒇(𝒙) = 𝟓𝒙 − 𝟕 Answer:𝒇(𝒙) = 𝟓𝒙 Answer:𝒇(𝒙) = 𝒙𝟐 + 𝟓

    Answer:𝒇(𝒙) = 𝒇(𝒙 − 𝟏) + 𝟓 𝒇(𝟏) = −𝟐

    Answer:𝒇(𝒙) = 𝒇(𝒙 − 𝟏) ∙ 𝟓 𝒇(𝟏) = 𝟓

    Answer:𝒇(𝒙) = 𝒇(𝒙 − 𝟏) + 𝟐𝒙 − 𝟏 𝒇(𝟏) = 𝟔

    Answer:Different,notexpectedstudentscancreateyet.

    Answer:𝒇(𝒙) = 𝟐𝒙Answer:𝒇(𝒙) = 𝒙𝟐 Answer:𝒇(𝒙) = 𝟐𝒙 − 𝟏

    Answer:𝒇(𝒙) = 𝟓𝒙 − 𝟕 Answer:𝒇(𝒙) = 𝟓𝒙 Answer:𝒇(𝒙) = 𝒙𝟐 + 𝟓

  • SECONDARY MATH II // MODULE 1

    QUADRATIC FUNCTIONS – 1.1

    Mathematics Vision Project

    Licensed under the Creative Commons Attribution CC BY 4.0

    mathematicsvisionproject.org

    1.1

    Needhelp?Visitwww.rsgsupport.org

    GO Topic:RatesofChangeIdentifytherateofchangeineachoftherepresentationsbelow.

    11.

    12. 13.

    x f(x)

    25 65

    26 68

    27 71

    28 74

    14.

    f 0 = 7; f n + 1 = f n + 5

    15.

    16.

    Slopeof𝐴𝐵

    A(-3,12)B(-11,-16)

    17.Georgeisloadingfreightintoanelevator.Henoticesthattheweightlimitfortheelevatoris1000lbs.He

    knowsthatheweighs210lbs.Hehasloaded15boxesintotheelevator.Eachboxweighs50lbs.Identify

    therateofchangeforthissituation.

    18.

    Independentvariable 4 5 6 7 8

    Dependentvariable 5 5.5 6 6.5 7

    19.

    𝑓 −4 = 24 𝑎𝑛𝑑 𝑓 6 = −36

    4

    3

    2

    1

    –1

    –2

    –3

    –4

    –6 –4 –2 2 4 6

    4

    3

    2

    1

    –1

    –2

    –3

    –4

    –6 –4 –2 2 4 6

    4

    3

    2

    1

    –1

    –2

    –3

    –4

    –6 –4 –2 2 4 6

    Answer:4Answer:-3

    Answer:3

    Answer:5

    Answer:𝟐𝟓

    Answer:𝟕𝟐= 𝟑.𝟓

    Answer:50lbsperbox

    Answer:.5

    Answer:-6